- #1

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Confused on where to start. Do you take the energy created by the wind needs to equal the energy required to move the water from 36.5 m deep to 2.3 m above the ground? Any help is appreciated

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- Thread starter Jacob87411
- Start date

- #1

- 171

- 1

Confused on where to start. Do you take the energy created by the wind needs to equal the energy required to move the water from 36.5 m deep to 2.3 m above the ground? Any help is appreciated

- #2

- 335

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- #3

- 171

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Isnt rotational energy given by E=Iw^2? What is I or do you need to find it

- #4

lightgrav

Homework Helper

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since this whole scenario is STEADY.

Wind has Kinetic Energy Density ... 1/2 rho v^2 ...

some wind goes thru (pierces) the windmill "disk" Area each second.

How much KE does that carry? (what's the mass flow rate?) per minute?

what mass water would 28% of that Energy lift 38.8 meters in Earth gravity?

- #5

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This equals 117.74 J. Every second this hits the total area of the windmill which is 4.155 m^2. So the total energy on the windmill is (.28)(117.74)(4.155) = 137 J every second on the windmill. We need the amount every minute so 137*60 = 8220 J.

So we have 8220 J to move the water. Is that right so far?

- #6

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So the mass of air hitting it must be? Think a bit. I don't like giving you everything readymade.

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